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4700=1/2x^2
We move all terms to the left:
4700-(1/2x^2)=0
Domain of the equation: 2x^2)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
-1/2x^2+4700=0
We multiply all the terms by the denominator
4700*2x^2-1=0
Wy multiply elements
9400x^2-1=0
a = 9400; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·9400·(-1)
Δ = 37600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{37600}=\sqrt{400*94}=\sqrt{400}*\sqrt{94}=20\sqrt{94}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{94}}{2*9400}=\frac{0-20\sqrt{94}}{18800} =-\frac{20\sqrt{94}}{18800} =-\frac{\sqrt{94}}{940} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{94}}{2*9400}=\frac{0+20\sqrt{94}}{18800} =\frac{20\sqrt{94}}{18800} =\frac{\sqrt{94}}{940} $
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